NCERT Solutions and competency-based questions for Class 10 Science Chapter 1 Chemical Reactions and Equations.

NCERT Solutions & Competency-Based Questions – Class 10 Science Chapter 1: Chemical Reactions and Equations

This article provides NCERT Solutions and competency-based questions for Class 10 Science Chapter 1 – Chemical Reactions and Equations. The answers are explained in simple, student-friendly language to help you understand important concepts, practise application-based questions, and prepare effectively for the CBSE board examination.

📘 Need to revise the chapter first? Read our complete Chemical Reactions and Equations Class 10 notes before starting the NCERT solutions.

📚 Table of Contents

  1. NCERT Solutions for Class 10 Science Chapter 1
  2. Chemical Reactions and Equations – NCERT Exercise Solutions
  3. Competency-Based Questions
  4. Exam Tips – Chemical Reactions and Equations
  5. Practice Worksheet
  6. Official NCERT Textbook Reference

NCERT Solutions for Class 10 Science Chapter 1

In-Text Questions

NCERT Solution Page 6

(i) Hydrogen + Chlorine → Hydrogen chloride

H₂ + Cl₂ → HCl

H₂ + Cl₂ → 2HCl

(ii) Barium chloride + Aluminium sulphate → Barium sulphate + Aluminium chloride

BaCl₂ + Al₂(SO₄)₃ → BaSO₄ + AlCl₃

3BaCl₂ + Al₂(SO₄)₃ → 3BaSO₄ + 2AlCl₃

(iii) Sodium + Water → Sodium hydroxide + Hydrogen

Na + H₂O → NaOH + H₂

2Na + 2H₂O → 2NaOH + H₂

(i) Solutions of barium chloride and sodium sulphate in water react to give insoluble barium sulphate and a solution of sodium chloride.

BaCl₂ + Na₂SO₄ → BaSO₄ + NaCl

BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)

(ii) Sodium hydroxide solution (in water) reacts with hydrochloric acid solution (in water) to produce sodium chloride solution and water.

NaOH + HCl → NaCl + H₂O

NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)

NCERT Solution Page 10

Answer: A yellow precipitate is formed. The precipitate is lead(II) iodide (PbI₂).

(ii) Write the balanced chemical equation for this reaction.

Answer:

Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq)

(iii) Is this also a double displacement reaction?

Answer: Yes, it is a double displacement reaction because the ions of the two reactants exchange places to form two new compounds, lead(II) iodide and potassium nitrate.

NCERT Solution Page 13

Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s)

AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

(i) 4Na(s) + O₂(g) → 2Na₂O(s)

(ii) CuO(s) + H₂(g) → Cu(s) + H₂O(l)

NCERT Exercises Questions Page 14

(a) Lead is getting reduced.

(b) Carbon dioxide is getting oxidised.

(c) Carbon is getting oxidised.

(d) Lead oxide is getting reduced.

(i) (a) and (b)

(ii) (a) and (c)

(iii) (a), (b) and (c)

(iv) all

The above reaction is an example of a:

(a) Combination reaction

(b) Double displacement reaction

(c) Decomposition reaction

(d) Displacement reaction

(a) Hydrogen gas and iron chloride are produced.

(b) Chlorine gas and iron hydroxide are produced.

(c) No reaction takes place.

(d) Iron salt and water are produced.

Fe(s) + 2HCl(aq) → FeCl₂(aq) + H₂(g) ↑

Answer: A chemical equation in which the number of atoms of each element is equal on both the reactant and product sides is called a balanced chemical equation.

A chemical equation should be balanced to satisfy the law of conservation of mass, according to which mass can neither be created nor destroyed in a chemical reaction. Therefore, the total number of atoms of each element must remain the same before and after the reaction.

H₂ + N₂ → NH₃

N₂ + 3H₂ → 2NH₃

CO + H₂ → CH₃OH

CO + 2H₂ → CH₃OH

CH₃COOH + C₂H₅OH → CH₃COOC₂H₅ + H₂O

CH₃COOH + C₂H₅OH → CH₃COOC₂H₅ + H₂O

CH₃COOH + NaOH → CH₃COONa + H₂O

CH₃COOH + NaOH → CH₃COONa + H₂O

(a) HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + H₂O

HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + H₂O

2HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + 2H₂O

(b) NaOH + H₂SO₄ → Na₂SO₄ + H₂O

NaOH + H₂SO₄ → Na₂SO₄ + H₂O

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

(c) NaCl + AgNO₃ → AgCl + NaNO₃

NaCl + AgNO₃ → AgCl + NaNO₃

NaCl + AgNO₃ → AgCl + NaNO₃

(d) BaCl₂ + H₂SO₄ → BaSO₄ + HCl

BaCl₂ + H₂SO₄ → BaSO₄ + HCl

BaCl₂ + H₂SO₄ → BaSO₄ + 2HCl

(a) Calcium hydroxide + Carbon dioxide → Calcium carbonate + Water

Ca(OH)₂ + CO₂ → CaCO₃ + H₂O

Ca(OH)₂ + CO₂ → CaCO₃ + H₂O

(b) Zinc + Silver nitrate → Zinc nitrate + Silver

Zn + AgNO₃ → Zn(NO₃)₂ + Ag

Zn + 2AgNO₃ → Zn(NO₃)₂ + 2Ag

(c) Aluminium + Copper chloride → Aluminium chloride + Copper

Al + CuCl₂ → AlCl₃ + Cu

2Al + 3CuCl₂ → 2AlCl₃ + 3Cu

(d) Barium chloride + Potassium sulphate → Barium sulphate + Potassium chloride

BaCl₂ + K₂SO₄ → BaSO₄ + KCl

BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl

(a) Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s)

2KBr(aq) + BaI₂(aq) → 2KI(aq) + BaBr₂(s)

(b) Zinc carbonate(s) → Zinc oxide(s) + Carbon dioxide(g)

ZnCO₃(s) → ZnO(s) + CO₂(g)

(c) Hydrogen(g) + Chlorine(g) → Hydrogen chloride(g)

H₂(g) + Cl₂(g) → 2HCl(g)

(d) Magnesium(s) + Hydrochloric acid(aq) → Magnesium chloride(aq) + Hydrogen(g)

Balanced equation:

Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)

CH₄ + 2O₂ → CO₂ + 2H₂O + Heat

CaCO₃ + Heat → CaO + CO₂

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + Energy

CaO + H₂O → Ca(OH)₂

CaCO₃ + Heat → CaO + CO₂

CaCO₃(s) + Heat → CaO(s) + CO₂(g)

2AgCl(s) + Sunlight → 2Ag(s) + Cl₂(g)

2H₂O(l) + Electricity → 2H₂(g) + O₂(g)

Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s)

Na₂SO₄(aq) + BaCl₂(aq) → BaSO₄(s) ↓ + 2NaCl(aq)

Na₂SO₄(aq) + BaCl₂(aq) → BaSO₄(s) ↓ + 2NaCl(aq)

Oil and fat-containing food items are flushed with nitrogen gas to prevent rancidity.

Nitrogen is relatively unreactive and prevents the fats and oils from coming in contact with oxygen, thereby slowing down their oxidation and keeping the food fresh for a longer time.

(a) Corrosion

(b) Rancidity

Competency-Based Questions

1. A student observes bubbles when zinc is added to dilute hydrochloric acid. What does this observation suggest? Name the gas likely to be produced.

Answer: The formation of bubbles suggests that a gas is being produced during the chemical reaction.

When zinc reacts with dilute hydrochloric acid, hydrogen gas (H₂) is produced.

Equation:

Therefore, the bubbles observed are of hydrogen gas.

2. A student balances an equation by changing H₂O into H₂O₂. Explain why this method is incorrect.

Answer: This method is incorrect because while balancing a chemical equation, we can change only the coefficients in front of the chemical formulae, not the formulae themselves.

Changing H₂O into H₂O₂ changes the substance itself: H₂O is water, whereas H₂O₂ is hydrogen peroxide.

Therefore, a chemical equation must be balanced by adjusting coefficients without changing the chemical formulae of the reactants or products.

3. A white solid appears when two colourless solutions are mixed. What type of reaction may have occurred? What is the white solid called?

Answer: A double displacement reaction may have occurred in which an insoluble substance is formed. Such a reaction is called a precipitation reaction.

The white solid formed is called a precipitate.

4. An iron nail is placed in copper sulphate solution. After some time, a change is observed. Explain why this can be considered a displacement reaction.

Answer: Iron is more reactive than copper, so it displaces copper from copper sulphate solution.

Reaction:

Fe(s) + CuSO₄(aq) → FeSO₄(aq) + Cu(s)

The blue copper sulphate solution gradually turns green, and a reddish-brown deposit of copper forms on the iron nail.

Therefore, it is a displacement reaction because iron displaces copper from its compound.

5. Two identical iron objects are kept under different conditions. One is kept dry, while the other is exposed to moist air. Which one is expected to rust faster? Give a reason.

Answer: The iron object exposed to moist air is expected to rust faster.

This is because rusting of iron requires both oxygen and moisture (water). The dry iron object has little or no moisture available, so rusting occurs much more slowly.

Answer: The chemical process responsible for the unpleasant smell is rancidity. It occurs when fats and oils in food get oxidised on exposure to air.

Two ways to slow down rancidity are:

  1. Store the food in an airtight container to reduce contact with oxygen.
  2. Keep the food refrigerated to slow down the oxidation process.

📝 Want more practice? Strengthen your preparation with our 21-page Class 10 Chemical Reactions and Equations Worksheet Pack, including MCQs, competency-based questions, balancing equations, assertion–reason questions and a complete answer key.

Colourful sticky notes showing important exam tips for Class 10 Science Chapter 1 Chemical Reactions and Equations.

📚 For the official textbook, visit the NCERT Class 10 Science textbook page.

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